How to set php condition with field value ?

Hello,

I create a "radio button" field, named for the example "Display div ?" with theses field values parameters : 1::Yes%% 0::No%%
Then, in my template, I want to display a div (or whatever) if the value of the field above is set on Yes, and hide the same div if the value is set on No.

For now, I have this code in the item.php of my template :

But it don't work.
I know the thing to change is : <?php if ($this->fields->display = '1') {
But I don't know the proper syntax.

Could you help me please ?

Thank in advance.

Hello,

you can read this FAQ article:
Using the raw value of a field inside a template file or inside a new custom field type

php code that you would use for field of type -radio- :
-- Note if you output is always the same then instead of custom code, you can do this:

1. Use a checkbox field instead with only 1 option
&nbsp;::Show Message%%

2. Put as prefix of every value: the HTML that you want to print
e.g.
<div>My notes</div>

This way the output of the field wil be:

Thank ggppdk for your answer.
I tried your first method but it doesn't work for me. I don't know why.
I obviously replace field_19 by my field name but no success.

I tried your second method with prefix value and it's working but not very convenient for me.

But isn't there a method in the item.php file to catch a field value and set it in a php condition otherwise than the first method that you wrote above ?

This syntax, for example, works great :
I want to replace NULL by 0 or 1 (the field value) or whatever else but I don't find the syntax nor I don't know if it could work.
I tried this, without success : etc.

Thank in advance.

Hello

You need the field ID and the field name:

Try (replace 19 with your field ID):

Sorry, but it doesn't work for me.
I put this in the template : Where 265 is my field ID.
But no value is displaying on the item view.

Hello

265 ?

just asking
you have created (and delete some) 250 different fields ??